Class 12 Chemistry Electrochemistry Magical Series Assignment

 

 

Class 12 Chemistry

Chapter 3 – Electrochemistry

Magical Series Assignment 3

 

Q.1.     For the cell reaction,

Ni(s) | Ni2+(aq) || Ag+(aq) | Ag(s)

Calculate the equilibrium constant at 25°C. How much maximum work would be obtained by operation of this cell?

EoNi2+/Ni = –0.25 V and EoAg+/Ag = 0.80 V

Q.2.     Calculate the standard cell potential of the galvanic cell in which the following reaction takes place:

Fe2+(aq) + Ag+ (aq) Fe3+(aq) + Ag(s)

Calculate the ∆rGo and equilibrium constant of the reaction.

(EoAg+/Ag = 0.80 V; EoFe3+/Fe2+ = 0.77 V)

Q.3.     Calculate the emf of following cell at 298 K:

Mg(s) | Mg2+(0.1 M) || Cu2+(0.01 M) | Cu(s)

[Given: Eocell = +2.71 V, 1 F = 96500 C mol–1]

Q.4.     Estimate the minimum potential difference needed to reduce Al2O3 at 500 °C. The Gibbs energy change for the decomposition reaction,

Image001  is 960 kJ (F = 96500 C mol–1)

Q.5.     Calculate the emf of the following cell at 298 K:

Fe(s) | Fe2+(0.001 M) || H+(l M) | H2(g)(1 bar), Pt(s)

(Given Eocell = +0.44 V)

Q.6.     Calculate the emf of the following cell at 25°C:

Ag(s) | Ag+(10–3 M) || Cu2+(10–1 M) | Cu(s)

Given: Eocell = +0.46 V and log 10" = n.

Q.7.     In the button cell, widely used in watches, the following reaction takes place.

Zn(s) + Ag2O(s) + H2O(l) Zn2+(aq) + 2Ag(s) + 2OH(aq)

Determine Eo and ∆Go for the reaction.

[Given: EoAg+/Ag = +0.80 V, EoZn2+/Zn = –0.76 V]

Q.8.     A voltaic cell is set up at 25°C with the following half cells:

Al/Al3+(0.001 M) and Ni/Ni2+(0.50 M)

Write an equation for the reaction that occurs when the cell generates an electric current and determine the cell potential.

EoNi2+/Ni = –0.25 V and EoAl3+/Al = –1.66 V. (log 8 × 10–6 = –5.09)

Q.9.     The cell in which the following reaction occurs:

2Fe3+(aq) + 2I(aq) 2Fe2+(aq) + I2(s)

has Eocell = 0.236 V at 298 K. Calculate the standard Gibbs energy and the equilibrium constant of the cell reaction.

(Antilog of 6.5 = 3.162 × 106; of 8.0 = 10 × 108; of 8.5 = 3.162 × 108)

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