Class 7 Mathematics
Chapter 13 - Exponents and Powers
Chapter Notes

Sometimes, it is very difficult to read, understand and compare very large numbers.

E.g., distance between Sun and Saturn is 1,433,500,000,000 m, distance between Saturn and Uranus is 1,439,000,000,000 m.

To make these numbers easy to read, understand and compare, we use the concept of exponents.

Exponents

The concept of exponent makes the representation of large numbers easier.

Example: let a number 10,000

We can write 10,000 = 10 × 10 × 10 × 10 = 104

Here the notation 104 is the short notation of 10 × 10 × 10 × 10 i.e. 10, 000

So, 104 is the exponential form of 10,000

Here 10 is called the base and 4 the exponent. The number 104 is read as 10 raised to the power of 4 or fourth power of 10.

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Similarly, 1,000 = 10 × 10 × 10 × 10 = 103

So, 103 is the exponent form of 1,000

Similarly, 1,00,000 = 10 × 10 × 10 × 10 × 10 = 105

105 is the exponential form of 1,00,000

We can use numbers like 10, 100, 100, etc to write the numbers in expanded form.

Example: 

12534 

= 1 × 10000 + 2 × 1000 + 5 × 100 + 3 × 10 + 4 × 1

= 1 × 104 + 2 × 103 + 5 × 102 + 3 × 10 + 4

The numbers which have base other than 10 can also be represented in exponent form.

64  = 2 × 2 × 2 × 2 × 2 × 2 

= 26

Here, 2 is the base and 6 is the exponent.

Similarly, 125 = 5 × 5 × 5 = 53

81 = 3 × 3 × 3 × 3 = 34

243 = 3 × 3 × 3 × 3 × 3 = 35 

We can also write the negative numbers in exponent form.

Example: 

−27 

= (−3) × (−3) × (−3) = (−3)3

−32 

= (−2) ×(−2) × (−2) × (−2) × (−2) = (−2)5

−125 

= (−5) × (−5) × (−5) = (−5)3

There are numbers which have more than one base. We can also write these numbers in exponent form.

Example: 

36 = 2 × 2 × 3 × 3 = 22 × 33  

= 2233 

675 = 3 × 3 × 3 × 5 × 5 = 33 × 52  

= 3352

1296 = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 3 

= 24 × 34 

= 2434

Question: Express the following in exponential form:

(i) 6 × 6 × 6 × 6

(ii) t × t

(iii) b × b × b × b

(iv) 5 × 5 × 7 × 7 × 7

(v) 2 × 2 × a × a

(vi) a × a × a × c × c × c × c × d

Solution:

(i) 6 × 6 × 6 × 6 

= 64

(ii) t × t 

= t2

(iii) b × b × b × b 

= b4

(iv) 5 × 5 × 7 × 7 × 7 

= 52 × 73

(v) 2 × 2 × a × a 

= 22 × a2

(vi) a × a × a × c × c × c × c × d 

= a3 × c4 × d

Question: Identify the greater number, wherever possible, in each of the following:

(i) 43 and 34

(ii) 53 or 35

(iii) 28 or 82

(iv) 1002 or 2100

(v) 210 or 102

Solution:

(i)  43 = 4 × 4 × 4 = 64

34 = 3 × 3 × 3 × 3 = 81 

Since 64 < 81

So, 34 is greater than 43

(ii) 53 = 5 × 5 × 5 = 125

35 = 3 × 3 × 3 × 3 × 3 = 243

Since 125 < 243

So, 35 is greater than 53 

(iii) 28 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 256

82 = 8 × 8 = 64

Since, 256 > 64

Thus, 28 is greater than 82

(iv) 1002 = 100 × 100 = 10,000

2100 = 27 × 27 × 286 

= 128 × 128 × 286 

= 16,384 × 286

Since, 10,000 < 16,384 × 286

Thus, 2100 is greater than 1002.

(v) 210 = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 

= 1,024

102 = 10 × 10 = 100

Since, 1,024 > 100

Thus, 210 is greater than 102

Laws of Exponents

Numbers in exponential form obey certain laws, which are discribed as follows:

(1) Multiplying Powers with the Same Number

For any non−zero integer a, where m and n are whole numbers,

am × an = am + n

Example: 

34 × 32 = 34 + 2 = 36

(2) Dividing Powers with the Same Number

For any non−zero integer a, where m and n are whole numbers and m > n,

am / an = am − n

Example: 

34 / 32 = 34 − 2 = 32

(3) Taking Power of a Power:

For any non−zero integer a, where m and n are whole numbers,

(am )n = am × n

Example: 

(34 )2 = 34 × 2 = 38

(4) Multiplying Powers with the Same Exponents

For any non−zero integer a, where m is any whole numbers,

am × bm = (a × b)= (ab)m

Example: 

23 × 33 = (2 × 3)= 63

(5) Dividing Powers with the Same Exponents

For any non−zero integer a and b, where m is any whole numbers,

am / bm = (a / b)m

Example: 

23 / 33 = (2/3)3

(6) Any number (except 0) raised to the power 0 is always 1.

a0 = 1  (a ≠ 0)

Example: 

30 = 1, (1000)0 = 1, (−5)0 = 1


Question: Simplify

(i) {(25)2 × 73}/(83 × 7)

(ii) (25 × 52 × t8)/(103 × t4)

(iii) (35 × 105 × 25)/(57 × 65)

Solution:

(i) {(25)2 × 73}/(83 × 7)

= (25×2 × 73)/{(23)3 × 7)} 

= (210 × 73)/(23×3 × 7)

= (210 × 73)/(29 × 7)

= 210−9 × 73−1

= 2 × 72

= 2 × 49

= 98

(ii) (25 × 52 × t8)/(103 × t4)

=(52 × 52 × t8)/{(5 × 2)3 × t4}

= (52+2 × t8)/(53 × 23 × t4)

= (54 × t8)/(53 × 23 × t4)

= (54−3 × t8−4)/8

= 5t4/8

(iii) (35 × 105 × 25)/(57 × 65)

= {(35 × (2 × 5)5 × 52)}/{57 × (2 × 3)5}

= (35 × 25 × 55+2)/(57 × 25 × 35)

= (35 × 25 × 57)/(57 × 25 × 35)

= 35−5 × 25−5 × 57−7

= 30 × 20 × 50

= 1 × 1 × 1

= 1

Decimal Number System

We can express a large number in terms of 10s.

Example: let a number is 35246

Here, 3 is at ten thousand place, 5 is at thousand place, 2 is at hundred palce, 4 is at 10 tenth place and 6 is at unit place. So, 35246 can be written as

35246 

= 3 × 10000 + 5 × 1000 + 2 × 100 + 4 × 10 + 6 × 1

= 3 × 104 + 5 × 103 + 2 × 102 + 4 × 101 + 6 × 100

Similarly, expansion of 250374 will be as follows:

250374 

= 2 × 100000 + 5 × 10000 + 0 × 1000 + 3 × 100 + 7 × 10 + 4 × 1

= 2 × 105 + 5 × 104 + 0 × 103 + 3 × 102 + 7 × 101 + 4 × 100

= 2 × 105 + 5 × 104 + 3 × 102 + 7 × 101 + 4 × 100

Question: Write the following numbers in the expanded form:

279404, 3006194, 2806196, 120719, 20068

Solution:

(i) 2,79,404

= 2,00,000 + 70,000 + 9,000 + 400 + 00 + 4

= 2 × 100000 + 7 × 10000 + 9 × 1000 + 4 × 100 + 0 × 10 + 4 × 1

= 2 × 105 + 7 × 104 + 9 × 103 + 4 × 102 + 0 × 101 + 4 × 100

(ii) 30,06,194

= 30,00,000 + 0 + 0 + 6,000 + 100 + 90 + 4

= 3 × 1000000 + 0 × 100000 + 0 × 10000 + 6 × 1000 + 1 × 100 + 9 × 101 + 4 × 1

= 3 × 106 + 0 × 105 + 0 × 104 + 6 × 103 + 1 × 102 + 9 × 101 + 4 × 100

(iii) 28,06,196

= 20,00,000 + 8,00,000 + 0 + 6,000 + 100 + 90 + 6

= 2 × 1000000 + 8 × 100000 + 0 × 10000 + 6 × 1000 + 1 × 100 + 9 × 10 + 6 × 1

= 2 × 106 + 8 × 105 + 0 × 104 + 6 × 103 + 1 × 102 + 9 × 101 + 6 × 100

(iv) 1,20,719

= 1,00,000 + 20,000 + 0 + 700 + 10 + 9

= 1 × 100000 + 2 × 10000 + 0 × 1000 + 7 × 100 + 1 × 10 + 9 × 1

= 1 × 105 + 2 × 104 + 0 × 103 + 7 × 102 + 1 × 101 + 9 × 100

(v) 20,068

= 20,000 + 00 + 00 + 60 + 8

= 2 × 10000 + 0 × 1000 + 0 × 100 + 6 × 10 + 8 × 1

= 2 × 104 + 0 × 103 + 0 × 102 + 6 × 101 + 8 × 100

Expressing Large Number in The Standard Form

We know that reading, writing and understanding a large number is not convenient. So, to make it convenient, we use the concept of powers.

Any number can be expressed as a decimal number between 1.0 and 10.0 including 1.0 multiplied by a power of 10. Such a form of a number is called its standard form.

Example: Let a number be 3500

We can express this number in many ways using exponent.

3500 = 35 × 100 = 35 × 102

3500 = 350 × 10 = 350 × 101

3500 = 3.5 × 1000 = 3.5 × 103

3500 = 0.35 × 10000 = 3.5 × 104

All of these are the representation of the number 3500 in exponent form. But the standard form of the number 3500 is that number which is expressed as number between 1 and 10.

So, 3500 = 3.5 × 1000 = 3.5 × 10is the standard form of the number 3500

Similarly, 12756000

= 12756 × 1000

= 1.2756 × 1000 × 10000

= 1.2756 × 107

Question: Express the following numbers in standard form:

(i) 5,00,00,000

(ii) 70,00,000

(iii) 3,18,65,00,000

(iv) 3,90,878

(v) 39087.8

(vi) 3908.78

Solution:

(i) 5,00,00,000

= 5 × 1,00,00,000

= 5 × 107

(ii) 70,00,000

= 7 × 10,00,000

= 7 × 106

(iii) 3,18,65,00,000

= 31865 × 100000

= 3.1865 × 10000 × 100000

= 3.1865 × 109

(iv) 3,90,878

= 3.90878 × 100000

= 3.90878 × 105

(v) 39087.8

= 3.90878 × 10000

= 3.90878 × 104

(vi) 3908.78

= 3.90878 × 1000

= 3.90878 × 103


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